Optimal. Leaf size=197 \[ -\frac{(d+e x)^{3/2} (-5 a B e+A b e+4 b B d)}{4 b^2 (a+b x) (b d-a e)}+\frac{3 e \sqrt{d+e x} (-5 a B e+A b e+4 b B d)}{4 b^3 (b d-a e)}-\frac{3 e (-5 a B e+A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{7/2} \sqrt{b d-a e}}-\frac{(d+e x)^{5/2} (A b-a B)}{2 b (a+b x)^2 (b d-a e)} \]
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Rubi [A] time = 0.146902, antiderivative size = 197, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.227, Rules used = {78, 47, 50, 63, 208} \[ -\frac{(d+e x)^{3/2} (-5 a B e+A b e+4 b B d)}{4 b^2 (a+b x) (b d-a e)}+\frac{3 e \sqrt{d+e x} (-5 a B e+A b e+4 b B d)}{4 b^3 (b d-a e)}-\frac{3 e (-5 a B e+A b e+4 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{7/2} \sqrt{b d-a e}}-\frac{(d+e x)^{5/2} (A b-a B)}{2 b (a+b x)^2 (b d-a e)} \]
Antiderivative was successfully verified.
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Rule 78
Rule 47
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(A+B x) (d+e x)^{3/2}}{(a+b x)^3} \, dx &=-\frac{(A b-a B) (d+e x)^{5/2}}{2 b (b d-a e) (a+b x)^2}+\frac{(4 b B d+A b e-5 a B e) \int \frac{(d+e x)^{3/2}}{(a+b x)^2} \, dx}{4 b (b d-a e)}\\ &=-\frac{(4 b B d+A b e-5 a B e) (d+e x)^{3/2}}{4 b^2 (b d-a e) (a+b x)}-\frac{(A b-a B) (d+e x)^{5/2}}{2 b (b d-a e) (a+b x)^2}+\frac{(3 e (4 b B d+A b e-5 a B e)) \int \frac{\sqrt{d+e x}}{a+b x} \, dx}{8 b^2 (b d-a e)}\\ &=\frac{3 e (4 b B d+A b e-5 a B e) \sqrt{d+e x}}{4 b^3 (b d-a e)}-\frac{(4 b B d+A b e-5 a B e) (d+e x)^{3/2}}{4 b^2 (b d-a e) (a+b x)}-\frac{(A b-a B) (d+e x)^{5/2}}{2 b (b d-a e) (a+b x)^2}+\frac{(3 e (4 b B d+A b e-5 a B e)) \int \frac{1}{(a+b x) \sqrt{d+e x}} \, dx}{8 b^3}\\ &=\frac{3 e (4 b B d+A b e-5 a B e) \sqrt{d+e x}}{4 b^3 (b d-a e)}-\frac{(4 b B d+A b e-5 a B e) (d+e x)^{3/2}}{4 b^2 (b d-a e) (a+b x)}-\frac{(A b-a B) (d+e x)^{5/2}}{2 b (b d-a e) (a+b x)^2}+\frac{(3 (4 b B d+A b e-5 a B e)) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b d}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{4 b^3}\\ &=\frac{3 e (4 b B d+A b e-5 a B e) \sqrt{d+e x}}{4 b^3 (b d-a e)}-\frac{(4 b B d+A b e-5 a B e) (d+e x)^{3/2}}{4 b^2 (b d-a e) (a+b x)}-\frac{(A b-a B) (d+e x)^{5/2}}{2 b (b d-a e) (a+b x)^2}-\frac{3 e (4 b B d+A b e-5 a B e) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{4 b^{7/2} \sqrt{b d-a e}}\\ \end{align*}
Mathematica [C] time = 0.0670306, size = 96, normalized size = 0.49 \[ \frac{(d+e x)^{5/2} \left (\frac{e (-5 a B e+A b e+4 b B d) \, _2F_1\left (2,\frac{5}{2};\frac{7}{2};\frac{b (d+e x)}{b d-a e}\right )}{(b d-a e)^2}+\frac{5 (a B-A b)}{(a+b x)^2}\right )}{10 b (b d-a e)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.018, size = 360, normalized size = 1.8 \begin{align*} 2\,{\frac{eB\sqrt{ex+d}}{{b}^{3}}}-{\frac{5\,A{e}^{2}}{4\,b \left ( bxe+ae \right ) ^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}+{\frac{9\,Ba{e}^{2}}{4\,{b}^{2} \left ( bxe+ae \right ) ^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-{\frac{eBd}{b \left ( bxe+ae \right ) ^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-{\frac{3\,Aa{e}^{3}}{4\,{b}^{2} \left ( bxe+ae \right ) ^{2}}\sqrt{ex+d}}+{\frac{3\,Ad{e}^{2}}{4\,b \left ( bxe+ae \right ) ^{2}}\sqrt{ex+d}}+{\frac{7\,B{a}^{2}{e}^{3}}{4\,{b}^{3} \left ( bxe+ae \right ) ^{2}}\sqrt{ex+d}}-{\frac{11\,Bad{e}^{2}}{4\,{b}^{2} \left ( bxe+ae \right ) ^{2}}\sqrt{ex+d}}+{\frac{eB{d}^{2}}{b \left ( bxe+ae \right ) ^{2}}\sqrt{ex+d}}+{\frac{3\,A{e}^{2}}{4\,{b}^{2}}\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{ \left ( ae-bd \right ) b}}}} \right ){\frac{1}{\sqrt{ \left ( ae-bd \right ) b}}}}-{\frac{15\,Ba{e}^{2}}{4\,{b}^{3}}\arctan \left ({b\sqrt{ex+d}{\frac{1}{\sqrt{ \left ( ae-bd \right ) b}}}} \right ){\frac{1}{\sqrt{ \left ( ae-bd \right ) b}}}}+3\,{\frac{eBd}{{b}^{2}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.50622, size = 1432, normalized size = 7.27 \begin{align*} \left [\frac{3 \,{\left (4 \, B a^{2} b d e -{\left (5 \, B a^{3} - A a^{2} b\right )} e^{2} +{\left (4 \, B b^{3} d e -{\left (5 \, B a b^{2} - A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (4 \, B a b^{2} d e -{\left (5 \, B a^{2} b - A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{b^{2} d - a b e} \log \left (\frac{b e x + 2 \, b d - a e - 2 \, \sqrt{b^{2} d - a b e} \sqrt{e x + d}}{b x + a}\right ) - 2 \,{\left (2 \,{\left (B a b^{3} + A b^{4}\right )} d^{2} -{\left (17 \, B a^{2} b^{2} - A a b^{3}\right )} d e + 3 \,{\left (5 \, B a^{3} b - A a^{2} b^{2}\right )} e^{2} - 8 \,{\left (B b^{4} d e - B a b^{3} e^{2}\right )} x^{2} +{\left (4 \, B b^{4} d^{2} -{\left (29 \, B a b^{3} - 5 \, A b^{4}\right )} d e + 5 \,{\left (5 \, B a^{2} b^{2} - A a b^{3}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{8 \,{\left (a^{2} b^{5} d - a^{3} b^{4} e +{\left (b^{7} d - a b^{6} e\right )} x^{2} + 2 \,{\left (a b^{6} d - a^{2} b^{5} e\right )} x\right )}}, \frac{3 \,{\left (4 \, B a^{2} b d e -{\left (5 \, B a^{3} - A a^{2} b\right )} e^{2} +{\left (4 \, B b^{3} d e -{\left (5 \, B a b^{2} - A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (4 \, B a b^{2} d e -{\left (5 \, B a^{2} b - A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{-b^{2} d + a b e} \arctan \left (\frac{\sqrt{-b^{2} d + a b e} \sqrt{e x + d}}{b e x + b d}\right ) -{\left (2 \,{\left (B a b^{3} + A b^{4}\right )} d^{2} -{\left (17 \, B a^{2} b^{2} - A a b^{3}\right )} d e + 3 \,{\left (5 \, B a^{3} b - A a^{2} b^{2}\right )} e^{2} - 8 \,{\left (B b^{4} d e - B a b^{3} e^{2}\right )} x^{2} +{\left (4 \, B b^{4} d^{2} -{\left (29 \, B a b^{3} - 5 \, A b^{4}\right )} d e + 5 \,{\left (5 \, B a^{2} b^{2} - A a b^{3}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{4 \,{\left (a^{2} b^{5} d - a^{3} b^{4} e +{\left (b^{7} d - a b^{6} e\right )} x^{2} + 2 \,{\left (a b^{6} d - a^{2} b^{5} e\right )} x\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.90127, size = 319, normalized size = 1.62 \begin{align*} \frac{2 \, \sqrt{x e + d} B e}{b^{3}} + \frac{3 \,{\left (4 \, B b d e - 5 \, B a e^{2} + A b e^{2}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{4 \, \sqrt{-b^{2} d + a b e} b^{3}} - \frac{4 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{2} d e - 4 \, \sqrt{x e + d} B b^{2} d^{2} e - 9 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b e^{2} + 5 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{2} e^{2} + 11 \, \sqrt{x e + d} B a b d e^{2} - 3 \, \sqrt{x e + d} A b^{2} d e^{2} - 7 \, \sqrt{x e + d} B a^{2} e^{3} + 3 \, \sqrt{x e + d} A a b e^{3}}{4 \,{\left ({\left (x e + d\right )} b - b d + a e\right )}^{2} b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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